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Work Energy AND Power flash cards

Master Work Energy AND Power through 92 JEE Advanced-level recall cards, systematically structured one idea at a time. Revise concept-wise, identify the areas where you need improvement, and focus your preparation with greater precision.

Work Energy AND Power, question and answer

27 of this chapter's 92 cards, laid out open so you can read straight through. The remaining 65 are in the interactive deck, where the answer stays hidden until you commit to one.

  1. 1.Define work done by a constant force F\vec{F} over displacement d\vec{d}.

    W=Fd=FdcosθW = \vec{F}\cdot\vec{d} = Fd\cos\theta, where θ\theta is the angle between force and displacement. Work is a scalar with SI unit joule (J).

    Hint: Dot product of force and displacement.

  2. 2.For what angle between force and displacement is the work done (i) maximum positive, (ii) zero, (iii) maximum negative?

    (i) θ=0\theta = 0^\circ gives W=+FdW = +Fd; (ii) θ=90\theta = 90^\circ gives W=0W = 0; (iii) θ=180\theta = 180^\circ gives W=FdW = -Fd.

    Hint: cosθ\cos\theta controls the sign.

  3. 3.Is work a scalar or a vector? What are its dimensions?

    Work is a scalar. Dimensions: [ML2T2][M L^2 T^{-2}]. SI unit joule, 1 J=1 N⋅m1\text{ J} = 1\text{ N·m}.

    Hint: Force × distance.

  4. 4.Give the general integral expression for work done by a variable force along a path.

    W=FdrW = \int \vec{F}\cdot d\vec{r}. For 1-D, W=x1x2F(x)dxW = \int_{x_1}^{x_2} F(x)\,dx, which equals the area under the FF vs xx graph.

    Hint: Sum of infinitesimal Fdr\vec{F}\cdot d\vec{r}.

  5. 5.How do you read work done from a force–displacement (FFxx) graph?

    Work equals the signed area between the curve and the xx-axis. Area above the axis is positive work; area below is negative work.

    Hint: Integral = area.

  6. 6.State the work–energy theorem.

    The net work done by all forces on a particle equals the change in its kinetic energy: Wnet=ΔK=12mv212mu2W_{net} = \Delta K = \tfrac12 mv^2 - \tfrac12 mu^2.

    Hint: Net work = change in KE.

  7. 7.Does the work–energy theorem hold for variable forces and curved paths?

    Yes. It is a general result derived from Newton's second law and holds for constant or variable forces, straight or curved paths, in an inertial frame.

    Hint: General consequence of F=maF=ma.

  8. 8.Define kinetic energy and write its formula.

    Kinetic energy is the energy possessed by a body due to its motion: K=12mv2K = \tfrac12 mv^2. It is always non-negative and a scalar.

    Hint: Half m v squared.

  9. 9.Relate kinetic energy to linear momentum pp.

    K=p22mK = \dfrac{p^2}{2m}, equivalently p=2mKp = \sqrt{2mK}. Useful when momentum is known instead of velocity.

    Hint: Substitute v=p/mv = p/m.

  10. 10.Two bodies have equal momentum. Which has greater kinetic energy?

    Since K=p2/2mK = p^2/2m with equal pp, the lighter body (smaller mm) has greater kinetic energy.

    Hint: K1/mK \propto 1/m at fixed pp.

  11. 11.Two bodies have equal kinetic energy. Which has greater momentum?

    Since p=2mKp = \sqrt{2mK} with equal KK, the heavier body (larger mm) has greater momentum.

    Hint: pmp \propto \sqrt{m} at fixed KK.

  12. 12.If a body's speed is doubled, how does its kinetic energy change?

    KE becomes 4 times, since Kv2K \propto v^2. Tripling speed makes KE 9 times.

    Hint: Kv2K \propto v^2.

  13. 13.Can kinetic energy be negative? Can work be negative?

    Kinetic energy can never be negative (12mv20\tfrac12 mv^2 \ge 0). Work can be negative when force opposes displacement (cosθ<0\cos\theta < 0).

    Hint: KE always 0\ge 0; work can be -.

  14. 14.Define potential energy.

    Potential energy is energy stored in a system by virtue of the configuration/position of its parts in a conservative force field. Only changes in PE (not absolute value) are physically meaningful.

    Hint: Energy of configuration.

  15. 15.Write the gravitational PE near Earth's surface and state the reference dependence.

    U=mghU = mgh measured from a chosen reference level. The zero of UU is arbitrary; only differences ΔU\Delta U matter.

    Hint: mghmgh above a datum.

  16. 16.Define a conservative force.

    A force is conservative if the work it does is path-independent (depends only on endpoints), equivalently the work done in any closed loop is zero. A PE function can then be defined.

    Hint: Path-independent; zero round-trip work.

  17. 17.Give three examples each of conservative and non-conservative forces.

    Conservative: gravity, spring (elastic) force, electrostatic force. Non-conservative: friction, air drag, viscous force (and applied/normal forces in general).

    Hint: Fields vs dissipative.

  18. 18.How is a conservative force related to its potential energy in 1-D?

    F(x)=dUdxF(x) = -\dfrac{dU}{dx}. The force points toward decreasing potential energy.

    Hint: Negative slope of U(x)U(x).

  19. 19.Write the 3-D relation between a conservative force and potential energy.

    F=U=(Uxi^+Uyj^+Uzk^)\vec{F} = -\nabla U = -\left(\dfrac{\partial U}{\partial x}\hat{i} + \dfrac{\partial U}{\partial y}\hat{j} + \dfrac{\partial U}{\partial z}\hat{k}\right).

    Hint: Force = minus gradient of U.

  20. 20.Express the change in potential energy in terms of the conservative force.

    ΔU=UfUi=ifFdr\Delta U = U_f - U_i = -\int_i^f \vec{F}\cdot d\vec{r}, i.e. U(x)=Fdx+CU(x) = -\int F\,dx + C.

    Hint: PE = minus work by conservative force.

  21. 21.What does a positive slope of the U(x)U(x) curve tell you about the force?

    If dU/dx>0dU/dx > 0, then F=dU/dx<0F = -dU/dx < 0, so the force points in the x-x direction (toward lower UU).

    Hint: Force pushes downhill on the U-curve.

  22. 22.Define stable, unstable, and neutral equilibrium in terms of U(x)U(x).

    Equilibrium requires dU/dx=0dU/dx = 0. Stable: UU minimum (d2U/dx2>0d^2U/dx^2 > 0). Unstable: UU maximum (d2U/dx2<0d^2U/dx^2 < 0). Neutral: UU constant around the point.

    Hint: Minimum, maximum, flat of U.

  23. 23.State the principle of conservation of mechanical energy.

    If only conservative forces do work, the total mechanical energy E=K+UE = K + U remains constant: ΔK+ΔU=0\Delta K + \Delta U = 0.

    Hint: K + U constant with only conservative forces.

  24. 24.How is the work–energy theorem modified when non-conservative forces act?

    Wnc=ΔK+ΔU=ΔEW_{nc} = \Delta K + \Delta U = \Delta E. The work by non-conservative forces equals the change in total mechanical energy (usually negative for friction).

    Hint: Wnc=ΔEW_{nc} = \Delta E.

  25. 25.A block slides down a rough incline. Where does the lost mechanical energy go?

    It is converted mostly into heat (and some sound) due to friction: Wfriction=|W_{friction}| = mechanical energy lost. Total energy (including thermal) is still conserved.

    Hint: Friction → heat.

  26. 26.State the general (broad) law of conservation of energy.

    Energy can neither be created nor destroyed, only transformed from one form to another; the total energy of an isolated system is constant.

    Hint: Total energy is invariant.

  27. 27.Define power. Give its SI unit and dimensions.

    Power is the rate of doing work: P=dWdtP = \dfrac{dW}{dt}. SI unit watt (W), 1 W=1 J/s1\text{ W}=1\text{ J/s}; dimensions [ML2T3][M L^2 T^{-3}].

    Hint: Rate of work.

Open the interactive deck for the other 65 cards, with self-grading so the ones you keep missing come back.

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