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Wave ON String flash cards

Master Wave ON String through 96 JEE Advanced-level recall cards, systematically structured one idea at a time. Revise concept-wise, identify the areas where you need improvement, and focus your preparation with greater precision.

Wave ON String, question and answer

24 of this chapter's 96 cards, laid out open so you can read straight through. The remaining 72 are in the interactive deck, where the answer stays hidden until you commit to one.

  1. 1.What is a transverse wave?

    A wave in which particles of the medium oscillate perpendicular to the direction of wave propagation. Waves on a string are transverse.

    Hint: Direction of particle motion vs propagation.

  2. 2.Can a transverse mechanical wave travel through a gas or non-viscous liquid (bulk)?

    No. Transverse mechanical waves need a medium that supports shear stress, so they travel only through solids (and surfaces/strings), not through the bulk of gases or ideal liquids.

    Hint: Shear modulus required.

  3. 3.Write the general equation of a wave moving in the +x+x direction.

    y(x,t)=Asin(ωtkx+ϕ)y(x,t)=A\sin(\omega t-kx+\phi), equivalently y=Asin(kxωt)y=A\sin(kx-\omega t) (differs by sign/phase convention).

    Hint: ωtkx\omega t - kx for +x+x travel.

  4. 4.In y=Asin(ωtkx)y=A\sin(\omega t-kx), what does each symbol mean?

    AA = amplitude, ω\omega = angular frequency, kk = wave number, xx = position, tt = time; (ωtkx)(\omega t-kx) is the phase.

    Hint: Amplitude, angular freq, wave number.

  5. 5.How do you tell the direction of travel from a wave equation?

    If xx and tt appear in the combination (ωtkx)(\omega t-kx) the wave moves in +x+x; if (ωt+kx)(\omega t+kx) it moves in x-x. Opposite signs of x,tx,t term ⇒ +x+x.

    Hint: Same sign vs opposite sign.

  6. 6.Define wavelength λ\lambda.

    The spatial period: distance between two consecutive points in the same phase (e.g. crest to crest). k=2πλk=\dfrac{2\pi}{\lambda}.

    Hint: Crest to crest distance.

  7. 7.Define the wave number kk and its units.

    k=2πλk=\dfrac{2\pi}{\lambda}, the angular (radian) wave number; units rad/m. It is the phase change per unit length.

    Hint: 2π/λ2\pi/\lambda.

  8. 8.Define angular frequency ω\omega and time period TT.

    ω=2πT=2πf\omega=\dfrac{2\pi}{T}=2\pi f; TT is the time for one full oscillation of a particle. Units of ω\omega: rad/s.

    Hint: 2π/T2\pi/T.

  9. 9.State the fundamental relation between wave speed, frequency and wavelength.

    v=fλ=ωkv=f\lambda=\dfrac{\omega}{k}. The wave speed equals the ratio of angular frequency to wave number.

    Hint: v=ω/kv=\omega/k.

  10. 10.What is the phase of a wave and how does it vary?

    Phase =(ωtkx+ϕ)=(\omega t-kx+\phi). It increases with time at a fixed point and decreases with xx at fixed time (for +x+x wave).

    Hint: Argument of the sine.

  11. 11.What is phase difference for a path difference Δx\Delta x?

    Δϕ=kΔx=2πλΔx\Delta\phi=k\,\Delta x=\dfrac{2\pi}{\lambda}\Delta x. A path difference of λ\lambda gives phase difference 2π2\pi.

    Hint: kΔxk\,\Delta x.

  12. 12.What is the phase difference between two particles separated by λ/4\lambda/4?

    Δϕ=2πλλ4=π2\Delta\phi=\dfrac{2\pi}{\lambda}\cdot\dfrac{\lambda}{4}=\dfrac{\pi}{2} (90°).

    Hint: Fraction of 2π2\pi.

  13. 13.Distinguish wave velocity from particle velocity.

    Wave velocity v=ω/kv=\omega/k is constant and is the speed of energy/phase transport. Particle velocity vp=y/t=Aωcos(ωtkx)v_p=\partial y/\partial t=A\omega\cos(\omega t-kx) oscillates and varies with position/time.

    Hint: One constant, one oscillating.

  14. 14.Write the particle velocity for y=Asin(ωtkx)y=A\sin(\omega t-kx).

    vp=yt=Aωcos(ωtkx)v_p=\dfrac{\partial y}{\partial t}=A\omega\cos(\omega t-kx); its maximum is vp,max=Aωv_{p,\max}=A\omega.

    Hint: Differentiate w.r.t. tt.

  15. 15.Write the particle acceleration for y=Asin(ωtkx)y=A\sin(\omega t-kx).

    ap=2yt2=Aω2sin(ωtkx)=ω2ya_p=\dfrac{\partial^2 y}{\partial t^2}=-A\omega^2\sin(\omega t-kx)=-\omega^2 y; maximum magnitude Aω2A\omega^2.

    Hint: ω2y-\omega^2 y, like SHM.

  16. 16.Relation between particle velocity, slope of string, and wave velocity.

    vp=vyxv_p=-v\,\dfrac{\partial y}{\partial x}. Particle velocity ==-(wave speed)×\times(slope of the string).

    Hint: vp=vv_p=-v\cdot slope.

  17. 17.What is the slope y/x\partial y/\partial x for y=Asin(ωtkx)y=A\sin(\omega t-kx)?

    yx=Akcos(ωtkx)\dfrac{\partial y}{\partial x}=-Ak\cos(\omega t-kx). Maximum slope magnitude AkAk.

    Hint: Differentiate w.r.t. xx.

  18. 18.State the linear (1-D) wave equation.

    2yt2=v22yx2\dfrac{\partial^2 y}{\partial t^2}=v^2\,\dfrac{\partial^2 y}{\partial x^2}, where vv is the wave speed. Any y=f(x±vt)y=f(x\pm vt) satisfies it.

    Hint: Second derivatives in tt and xx.

  19. 19.How is wave speed read off from the differential wave equation?

    In 2yt2=v22yx2\dfrac{\partial^2 y}{\partial t^2}=v^2\dfrac{\partial^2 y}{\partial x^2}, the coefficient of the space second-derivative is v2v^2; also v=ω/kv=\omega/k.

    Hint: Coefficient is v2v^2.

  20. 20.Speed of a transverse wave on a stretched string.

    v=Tμv=\sqrt{\dfrac{T}{\mu}}, where TT is tension and μ\mu is linear mass density (mass per unit length).

    Hint: Tension over mass per length.

  21. 21.Define linear mass density μ\mu.

    μ=mL=ρA\mu=\dfrac{m}{L}=\rho A (mass per unit length), where ρ\rho is volume density and AA the cross-section area. Units kg/m.

    Hint: Mass per unit length.

  22. 22.How does wave speed on a string change if tension is quadrupled?

    vTv\propto\sqrt{T}, so quadrupling TT doubles vv.

    Hint: Square-root dependence.

  23. 23.How does wave speed depend on the string's thickness (same material)?

    μ=ρAr2\mu=\rho A\propto r^2, and v=T/μv=\sqrt{T/\mu}, so thicker string ⇒ larger μ\mu ⇒ smaller speed for the same tension.

    Hint: v1/μv\propto 1/\sqrt{\mu}.

  24. 24.When a wave passes from a thin to a thick string (same tension), what changes and what stays constant?

    Frequency ff stays constant (set by the source). Speed and wavelength decrease in the denser (thicker) string since v=T/μv=\sqrt{T/\mu} and λ=v/f\lambda=v/f.

    Hint: Frequency is fixed across a boundary.

Open the interactive deck for the other 72 cards, with self-grading so the ones you keep missing come back.

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