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Work Energy and Power flash cards

Master Work Energy and Power through 99 NEET-level recall cards, systematically structured one idea at a time. Revise concept-wise, identify the areas where you need improvement, and focus your preparation with greater precision.

Work Energy and Power, question and answer

30 of this chapter's 99 cards, laid out open so you can read straight through. The remaining 69 are in the interactive deck, where the answer stays hidden until you commit to one.

  1. 1.Define work done by a constant force.

    Work is the dot product of force and displacement: W=Fd=FdcosθW = \vec{F}\cdot\vec{d} = Fd\cos\theta, where θ\theta is the angle between F\vec{F} and displacement d\vec{d}.

    Hint: Scalar product of force and displacement.

  2. 2.Is work a scalar or vector quantity? What is its SI unit?

    Work is a scalar quantity. Its SI unit is the joule (J), where 1 J=1 Nm1\ \text{J} = 1\ \text{N}\cdot\text{m}.

    Hint: Dot product gives a scalar.

  3. 3.When is the work done by a force zero even though force and displacement are non-zero?

    When θ=90\theta = 90^\circ, i.e. force is perpendicular to displacement, since cos90=0\cos 90^\circ = 0. Example: centripetal force in uniform circular motion.

    Hint: Think perpendicular force.

  4. 4.What determines whether work done is positive, negative or zero?

    The angle θ\theta between force and displacement: positive if 0θ<900^\circ \le \theta < 90^\circ, zero if θ=90\theta = 90^\circ, negative if 90<θ18090^\circ < \theta \le 180^\circ.

    Hint: Sign of cosθ\cos\theta.

  5. 5.Give an example of negative work.

    Work done by friction on a moving body (force opposite to displacement, θ=180\theta = 180^\circ). Also work done by gravity on a body moving up.

    Hint: Force opposes motion.

  6. 6.What is the dimensional formula of work?

    [W]=[ML2T2][W] = [ML^2T^{-2}], same as energy.

    Hint: Force times distance.

  7. 7.How is work done by a variable force calculated?

    By integration: W=xixfFdxW = \int_{x_i}^{x_f} F\,dx (in 1D), which equals the area under the force–displacement graph.

    Hint: Integral of FF over displacement.

  8. 8.What does the area under a force–displacement (FF vs xx) graph represent?

    It represents the work done by the force. Area above the axis is positive work; area below is negative work.

    Hint: W=FdxW=\int F\,dx.

  9. 9.State the work–energy theorem.

    The net work done by all forces on a body equals the change in its kinetic energy: Wnet=ΔK=KfKi=12mv212mu2W_{net} = \Delta K = K_f - K_i = \tfrac{1}{2}mv^2 - \tfrac{1}{2}mu^2.

    Hint: Net work = change in KE.

  10. 10.Does the work–energy theorem hold for variable forces?

    Yes. The work–energy theorem Wnet=ΔKW_{net} = \Delta K is valid for both constant and variable forces, and along any path.

    Hint: It is general.

  11. 11.Define kinetic energy and give its formula.

    Kinetic energy is the energy possessed by a body due to its motion: K=12mv2K = \tfrac{1}{2}mv^2. It is a scalar and always non-negative.

    Hint: Energy of motion.

  12. 12.Relate kinetic energy to linear momentum.

    K=p22mK = \dfrac{p^2}{2m}, where p=mvp = mv is the linear momentum. Also p=2mKp = \sqrt{2mK}.

    Hint: Substitute v=p/mv=p/m.

  13. 13.If momentum of a body doubles, how does its kinetic energy change?

    Since K=p2/2mK = p^2/2m, doubling pp makes KK become 4 times the original (for constant mass).

    Hint: Kp2K\propto p^2.

  14. 14.If kinetic energy of a body increases by a factor of 4, how does momentum change?

    Since p=2mKp = \sqrt{2mK}, pKp \propto \sqrt{K}, so momentum doubles.

    Hint: pKp\propto\sqrt{K}.

  15. 15.Define potential energy.

    Potential energy is the energy possessed by a body due to its position or configuration in a force field. It is defined only for conservative forces.

    Hint: Energy of position/configuration.

  16. 16.Write the expression for gravitational potential energy near Earth's surface.

    U=mghU = mgh, where hh is height above a chosen reference level. Only the change ΔU=mgΔh\Delta U = mg\,\Delta h is physically meaningful.

    Hint: Depends on height.

  17. 17.Why is only the change in potential energy physically meaningful?

    Because the reference (zero) level of PE is arbitrary; forces depend on the gradient of PE, so a constant shift in UU has no physical effect.

    Hint: Zero level is a choice.

  18. 18.Relate a conservative force to its potential energy in one dimension.

    F=dUdxF = -\dfrac{dU}{dx}. Force is the negative gradient (slope) of the potential energy curve.

    Hint: Negative slope of U(x)U(x).

  19. 19.What is a conservative force? Give two examples.

    A force is conservative if the work done by it around any closed path is zero (path-independent work). Examples: gravitational force and spring (elastic) force.

    Hint: Path-independent, zero work in a loop.

  20. 20.What is a non-conservative force? Give an example.

    A force for which work done depends on the path taken and is non-zero over a closed loop. Example: friction and air resistance (viscous drag).

    Hint: Path-dependent, dissipative.

  21. 21.How can potential energy be defined for a conservative force?

    UfUi=Wconservative=ifFdrU_f - U_i = -W_{conservative} = -\int_{i}^{f}\vec{F}\cdot d\vec{r}. PE change equals negative of work done by the conservative force.

    Hint: ΔU=W\Delta U = -W.

  22. 22.State the principle of conservation of mechanical energy.

    If only conservative forces act, the total mechanical energy E=K+UE = K + U of a system remains constant: Ki+Ui=Kf+UfK_i + U_i = K_f + U_f.

    Hint: KE + PE = constant.

  23. 23.Under what condition is mechanical energy NOT conserved?

    When non-conservative forces (friction, air drag) do work, or when external forces add/remove energy. Then Δ(K+U)=Wnc\Delta(K+U) = W_{nc}.

    Hint: Friction present.

  24. 24.For a freely falling body, what happens to KE and PE?

    PE decreases and KE increases such that their sum stays constant (neglecting air resistance): mgh+12mv2=mgh + \tfrac{1}{2}mv^2 = constant.

    Hint: PE converts to KE.

  25. 25.Write the work done by a spring obeying Hooke's law when stretched by xx.

    Work done by the spring force is Wspring=12kx2W_{spring} = -\tfrac{1}{2}kx^2; work done against it (stored PE) is +12kx2+\tfrac{1}{2}kx^2.

    Hint: Spring force =kx=-kx.

  26. 26.Write the expression for elastic potential energy stored in a spring.

    U=12kx2U = \tfrac{1}{2}kx^2, where kk is the spring (force) constant and xx is the deformation from natural length.

    Hint: Half k x squared.

  27. 27.Is spring potential energy the same for compression and extension by equal amounts?

    Yes. Since U=12kx2U = \tfrac{1}{2}kx^2 depends on x2x^2, equal compression or extension stores the same PE.

    Hint: Ux2U\propto x^2.

  28. 28.What is the spring constant kk and its SI unit?

    kk measures spring stiffness; F=kxF = kx. Its SI unit is N/m (N m1\text{N m}^{-1}). Larger kk means a stiffer spring.

    Hint: Force per unit extension.

  29. 29.Define power and give its formula.

    Power is the rate of doing work (or energy transfer): P=dWdtP = \dfrac{dW}{dt}. Average power Pav=WtP_{av} = \dfrac{W}{t}.

    Hint: Work per unit time.

  30. 30.Express instantaneous power in terms of force and velocity.

    P=Fv=FvcosθP = \vec{F}\cdot\vec{v} = Fv\cos\theta, where v\vec{v} is the instantaneous velocity.

    Hint: Dot product of force and velocity.

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