Skip to main content
NEET Test Series — Practice smart, score high.

Modern Physics flash cards

Master Modern Physics through 103 NEET-level recall cards, systematically structured one idea at a time. Revise concept-wise, identify the areas where you need improvement, and focus your preparation with greater precision.

Modern Physics, question and answer

30 of this chapter's 103 cards, laid out open so you can read straight through. The remaining 73 are in the interactive deck, where the answer stays hidden until you commit to one.

  1. 1.What is the photoelectric effect?

    The emission of electrons from a metal surface when light of suitable frequency falls on it. The ejected electrons are called photoelectrons.

    Hint: Light in, electrons out.

  2. 2.What is the work function ϕ0\phi_0 of a metal?

    The minimum energy required to remove an electron from the metal surface. It equals hν0h\nu_0, where ν0\nu_0 is the threshold frequency.

    Hint: Minimum energy to free an electron.

  3. 3.What is threshold frequency ν0\nu_0?

    The minimum frequency of incident light below which no photoelectric emission occurs, no matter how intense the light. Related as ϕ0=hν0\phi_0 = h\nu_0.

    Hint: Below it, no emission at all.

  4. 4.Write Einstein's photoelectric equation.

    Kmax=hνϕ0K_{max} = h\nu - \phi_0, where KmaxK_{max} is the maximum kinetic energy of the emitted photoelectron and ϕ0\phi_0 is the work function.

    Hint: KE = photon energy − work function.

  5. 5.What is a photon?

    A quantum (packet) of light energy of magnitude E=hνE = h\nu. It has zero rest mass, travels at speed cc, and carries momentum p=h/λp = h/\lambda.

    Hint: Particle of light, E=hνE=h\nu.

  6. 6.What is threshold wavelength λ0\lambda_0?

    The maximum wavelength of incident light that can cause photoemission: λ0=hcϕ0\lambda_0 = \dfrac{hc}{\phi_0}. Longer wavelengths cannot eject electrons.

    Hint: Longest wavelength that still works.

  7. 7.How does maximum KE of photoelectrons depend on frequency of light?

    Kmax=hνϕ0K_{max} = h\nu - \phi_0, so KmaxK_{max} increases linearly with frequency ν\nu (for ν>ν0\nu > \nu_0) and is independent of light intensity.

    Hint: Linear in ν\nu, not intensity.

  8. 8.How does photoelectric current depend on intensity of light?

    At a fixed frequency above threshold, the number of photoelectrons per second (and hence the current) is directly proportional to the intensity.

    Hint: More light → more electrons, same KE.

  9. 9.What is stopping potential V0V_0?

    The minimum negative (retarding) potential applied to the collector at which the photoelectric current becomes zero. It satisfies eV0=KmaxeV_0 = K_{max}.

    Hint: Voltage that just stops the fastest electron.

  10. 10.Relation between stopping potential and frequency?

    eV0=hνϕ0eV_0 = h\nu - \phi_0, so V0=heνϕ0eV_0 = \dfrac{h}{e}\nu - \dfrac{\phi_0}{e}. A graph of V0V_0 vs ν\nu is a straight line of slope h/eh/e.

    Hint: Slope of V0V_0ν\nu line is h/eh/e.

  11. 11.Does stopping potential depend on intensity of light?

    No. Stopping potential depends only on the frequency of light and the metal's work function, not on intensity.

    Hint: Frequency decides it, not brightness.

  12. 12.Why does the photoelectric effect support the particle nature of light?

    Emission is instantaneous, depends on frequency (not intensity) with a threshold, and KmaxK_{max} rises with ν\nu — all explained by photons of energy hνh\nu, not by classical waves.

    Hint: Threshold + instant emission = photons.

  13. 13.Why is there no time lag in the photoelectric effect?

    A single photon delivers its whole energy hνh\nu to one electron in a single collision, so emission is essentially instantaneous (<109<10^{-9} s).

    Hint: One photon, one electron, at once.

  14. 14.What did classical wave theory fail to explain about the photoelectric effect?

    The existence of a threshold frequency, the independence of KmaxK_{max} from intensity, and the instantaneous emission. Wave theory predicted energy build-up over time.

    Hint: Wave theory got threshold and timing wrong.

  15. 15.What is the value of Planck's constant hh?

    h6.63×1034h \approx 6.63 \times 10^{-34} J s. It relates a photon's energy to its frequency: E=hνE = h\nu.

    Hint: 6.63×10346.63\times10^{-34} J s.

  16. 16.What is 1 electron volt (eV) in joules?

    1 eV=1.6×10191\ \text{eV} = 1.6 \times 10^{-19} J — the energy gained by an electron accelerated through a potential difference of 1 volt.

    Hint: 1.6×10191.6\times10^{-19} J.

  17. 17.State the dual nature of radiation.

    Light behaves as a wave (interference, diffraction, polarization) and as a stream of particles/photons (photoelectric effect, Compton effect). It exhibits wave–particle duality.

    Hint: Wave AND particle.

  18. 18.What is de Broglie's hypothesis?

    Every moving particle of momentum pp has an associated matter wave of wavelength λ=hp=hmv\lambda = \dfrac{h}{p} = \dfrac{h}{mv}.

    Hint: Matter has waves too.

  19. 19.Write the de Broglie wavelength in terms of kinetic energy.

    For a particle of mass mm and kinetic energy KK: λ=h2mK\lambda = \dfrac{h}{\sqrt{2mK}}.

    Hint: λ=h/2mK\lambda = h/\sqrt{2mK}.

  20. 20.de Broglie wavelength of an electron accelerated through potential VV?

    λ=h2meV1.227V\lambda = \dfrac{h}{\sqrt{2meV}} \approx \dfrac{1.227}{\sqrt{V}} nm (with VV in volts).

    Hint: λ1.227/V\lambda \approx 1.227/\sqrt{V} nm.

  21. 21.Why don't we observe the wave nature of a moving cricket ball?

    Its momentum is very large, so λ=h/p\lambda = h/p is extremely small (much smaller than any aperture), making diffraction/interference unobservable.

    Hint: Huge pp → tiny λ\lambda.

  22. 22.Which experiment confirmed the wave nature of electrons?

    The Davisson–Germer experiment, which showed electron diffraction from a nickel crystal, matching de Broglie's predicted wavelength.

    Hint: Davisson–Germer, electron diffraction.

  23. 23.How does de Broglie wavelength change if a particle's speed increases?

    Since λ=h/mv\lambda = h/mv, wavelength decreases as speed (momentum) increases; they are inversely related.

    Hint: Faster → shorter wave.

  24. 24.For the same KE, which has a longer de Broglie wavelength: an electron or a proton?

    The electron. Since λ=h/2mK\lambda = h/\sqrt{2mK}, the smaller mass gives the longer wavelength for equal kinetic energy.

    Hint: Lighter particle, longer wave.

  25. 25.What are the postulates of Bohr's model of hydrogen (in brief)?

    (1) Electrons orbit in stable stationary states without radiating. (2) Angular momentum is quantized: L=mvr=nh2πL = mvr = \dfrac{nh}{2\pi}. (3) Radiation is emitted/absorbed only when an electron jumps between orbits: hν=EiEfh\nu = E_i - E_f.

    Hint: Stationary orbits, quantized LL, jump = photon.

  26. 26.State Bohr's quantization of angular momentum.

    The angular momentum of the electron is an integral multiple of h2π\dfrac{h}{2\pi}: mvr=nh2πmvr = \dfrac{nh}{2\pi}, where n=1,2,3,n = 1,2,3,\dots

    Hint: L=nh/2πL = nh/2\pi.

  27. 27.What is the radius of the nnth Bohr orbit of hydrogen?

    rn=n2h2ε0πme2=0.529n2r_n = \dfrac{n^2 h^2 \varepsilon_0}{\pi m e^2} = 0.529\, n^2 Å. It increases as n2n^2.

    Hint: rnn2r_n \propto n^2; r1=0.53r_1 = 0.53 Å.

  28. 28.What is the Bohr radius?

    The radius of the smallest (n=1n=1) orbit of hydrogen: a0=0.529 A˚=0.529×1010a_0 = 0.529\ \text{Å} = 0.529 \times 10^{-10} m.

    Hint: Ground-state radius, 0.530.53 Å.

  29. 29.What is the energy of the nnth level of hydrogen?

    En=13.6n2E_n = -\dfrac{13.6}{n^2} eV. The energy is negative (bound) and increases (toward 0) as nn increases.

    Hint: En=13.6/n2E_n = -13.6/n^2 eV.

  30. 30.What is the ground-state energy of the hydrogen atom?

    E1=13.6E_1 = -13.6 eV. This is the most tightly bound state (n=1n=1).

    Hint: 13.6-13.6 eV at n=1n=1.

Open the interactive deck for the other 73 cards, with self-grading so the ones you keep missing come back.

Other ways to revise this chapter

Master this chapter with similar other learning materials.

Preparing students for India’s top institutes

Our students are currently into top technological and medical institutes of India.

  • IIT Bombay
  • IIT Delhi
  • IIT Madras
  • IIT Kanpur
  • IIT Kharagpur
  • IIT Roorkee
  • IIT Guwahati
  • IIT BHU Varanasi
  • AIIMS Delhi
  • NIT Tiruchirappalli
  • NIT Rourkela

Join QuestPix, Today!

Get notified first, with exam & curriculum updates, course & test series launch offers, motivation & success stories and free learning resources recommended by toppers.

Chat on WhatsApp