Skip to main content
NEET Test Series — Practice smart, score high.

EM Waves flash cards

Master EM Waves through 95 NEET-level recall cards, systematically structured one idea at a time. Revise concept-wise, identify the areas where you need improvement, and focus your preparation with greater precision.

EM Waves, question and answer

23 of this chapter's 95 cards, laid out open so you can read straight through. The remaining 72 are in the interactive deck, where the answer stays hidden until you commit to one.

  1. 1.What is displacement current?

    A current-like term Id=ε0dΦEdtI_d = \varepsilon_0 \dfrac{d\Phi_E}{dt} arising from a changing electric flux; it is not due to flow of charges but produces a magnetic field just like conduction current.

    Hint: Introduced by Maxwell; linked to changing ΦE\Phi_E.

  2. 2.Why did Maxwell introduce displacement current?

    To remove the inconsistency in Ampere's law: for a charging capacitor, no conduction current flows between the plates, yet a magnetic field exists there. The changing electric flux (displacement current) accounts for it.

    Hint: Ampere's law failed at a capacitor gap.

  3. 3.Write the expression for displacement current in terms of electric flux.

    Id=ε0dΦEdtI_d = \varepsilon_0 \dfrac{d\Phi_E}{dt}, where ΦE\Phi_E is the electric flux through the surface.

    Hint: Proportional to rate of change of ΦE\Phi_E.

  4. 4.How do conduction current and displacement current compare in a charging capacitor circuit?

    They are exactly equal in magnitude: Ic=Id=ε0dΦEdtI_c = I_d = \varepsilon_0 \dfrac{d\Phi_E}{dt}. This keeps the total current continuous across the capacitor gap.

    Hint: Continuity of current is preserved.

  5. 5.State the generalised (Ampere–Maxwell) law.

    Bdl=μ0(Ic+ε0dΦEdt)\oint \vec{B}\cdot d\vec{l} = \mu_0\left(I_c + \varepsilon_0 \dfrac{d\Phi_E}{dt}\right) — magnetic field is produced by conduction current plus displacement current.

    Hint: Ampere's law + displacement current term.

  6. 6.What key symmetry did Maxwell's addition of displacement current reveal?

    Just as a changing magnetic field produces an electric field (Faraday), a changing electric field produces a magnetic field. This symmetry between E\vec{E} and B\vec{B} leads to electromagnetic waves.

    Hint: Changing E ⟶ B, and changing B ⟶ E.

  7. 7.List the four Maxwell's equations (qualitatively, by name).

    1) Gauss's law for electricity (electric flux ∝ enclosed charge). 2) Gauss's law for magnetism (net magnetic flux = 0, no monopoles). 3) Faraday's law (changing B ⟶ EMF/E). 4) Ampere–Maxwell law (conduction + displacement current ⟶ B).

    Hint: Two Gauss, one Faraday, one Ampere–Maxwell.

  8. 8.What does Gauss's law for magnetism (BdA=0\oint \vec{B}\cdot d\vec{A} = 0) tell us?

    Net magnetic flux through any closed surface is zero, implying isolated magnetic monopoles do not exist; magnetic field lines are always continuous closed loops.

    Hint: No magnetic monopoles.

  9. 9.According to Maxwell, what does an accelerating charge produce?

    An accelerating (or oscillating) charge radiates energy in the form of electromagnetic waves. A charge oscillating with frequency ff produces EM waves of the same frequency ff.

    Hint: Only accelerated charges radiate EM waves.

  10. 10.Can a charge moving with uniform velocity produce electromagnetic waves?

    No. Only accelerated (or oscillating) charges radiate EM waves. Uniform velocity means zero acceleration, so no radiation.

    Hint: Acceleration is essential.

  11. 11.What is an electromagnetic wave?

    A wave consisting of oscillating electric and magnetic fields, mutually perpendicular and perpendicular to the direction of propagation, that travels through space (including vacuum) transporting energy.

    Hint: Coupled oscillating E and B fields.

  12. 12.Are electromagnetic waves transverse or longitudinal?

    Transverse — the electric field E\vec{E} and magnetic field B\vec{B} oscillate perpendicular to the direction of wave propagation.

    Hint: E and B ⟂ propagation direction.

  13. 13.State the mutual orientation of E\vec{E}, B\vec{B} and the direction of propagation in an EM wave.

    E\vec{E}, B\vec{B} and the propagation direction are mutually perpendicular. The wave travels along E×B\vec{E}\times\vec{B}.

    Hint: E×B\vec{E}\times\vec{B} gives propagation direction.

  14. 14.Do electromagnetic waves require a material medium to propagate?

    No. Unlike mechanical waves, EM waves can travel through vacuum. This is how sunlight reaches the Earth through empty space.

    Hint: They travel through vacuum.

  15. 15.What is the speed of electromagnetic waves in vacuum, and its formula?

    c=1μ0ε03×108c = \dfrac{1}{\sqrt{\mu_0 \varepsilon_0}} \approx 3\times 10^8 m/s, where μ0\mu_0 is the permeability and ε0\varepsilon_0 the permittivity of free space.

    Hint: c=1/μ0ε0c=1/\sqrt{\mu_0\varepsilon_0}.

  16. 16.What is the speed of an EM wave in a medium of permittivity ε\varepsilon and permeability μ\mu?

    v=1μεv = \dfrac{1}{\sqrt{\mu \varepsilon}}. Since με>μ0ε0\mu\varepsilon > \mu_0\varepsilon_0 for a material medium, v<cv < c.

    Hint: v=1/μεv=1/\sqrt{\mu\varepsilon}, always less than cc.

  17. 17.How is the speed of an EM wave in a medium related to refractive index nn?

    v=cnv = \dfrac{c}{n}, where n=μrεrn = \sqrt{\mu_r \varepsilon_r} is the refractive index. For non-magnetic media (μr1\mu_r \approx 1), nεrn \approx \sqrt{\varepsilon_r}.

    Hint: v=c/nv=c/n and n=μrεrn=\sqrt{\mu_r\varepsilon_r}.

  18. 18.State the relation between the magnitudes of E0E_0 and B0B_0 in an EM wave.

    c=E0B0c = \dfrac{E_0}{B_0}, i.e. E0=cB0E_0 = cB_0. The ratio of the amplitudes of the electric and magnetic fields equals the speed of light.

    Hint: E0/B0=cE_0/B_0 = c.

  19. 19.Which is larger in an EM wave, the electric field amplitude or the magnetic field amplitude (numerically)?

    Numerically the electric field is much larger: E0=cB0E_0 = cB_0 with c3×108c \approx 3\times10^8. But this does not mean E is 'stronger' — the energy is shared equally between the two fields.

    Hint: E0=cB0E_0 = cB_0; c is a large factor.

  20. 20.Write the standard expressions for the fields of a plane EM wave travelling along the x-axis.

    Ey=E0sin(kxωt)E_y = E_0 \sin(kx - \omega t) and Bz=B0sin(kxωt)B_z = B_0 \sin(kx - \omega t), where the E field is along y and B field along z.

    Hint: E and B in phase, perpendicular directions.

  21. 21.Are E\vec{E} and B\vec{B} in phase in an electromagnetic wave?

    Yes. In a plane EM wave in vacuum, E\vec{E} and B\vec{B} oscillate in phase — they reach their maxima and zeros at the same instants.

    Hint: They peak together.

  22. 22.How are the frequency and wavelength of an EM wave related to its speed?

    c=fλc = f\lambda (in vacuum), where ff is frequency and λ\lambda is wavelength. In a medium v=fλv = f\lambda, with frequency unchanged and wavelength reduced.

    Hint: c=fλc=f\lambda; f stays fixed across media.

  23. 23.When an EM wave enters a denser medium, which quantities change?

    Speed and wavelength decrease (both by factor nn); frequency remains unchanged because it is set by the source.

    Hint: Frequency constant; v and λ drop.

Open the interactive deck for the other 72 cards, with self-grading so the ones you keep missing come back.

Other ways to revise this chapter

Master this chapter with similar other learning materials.

Preparing students for India’s top institutes

Our students are currently into top technological and medical institutes of India.

  • IIT Bombay
  • IIT Delhi
  • IIT Madras
  • IIT Kanpur
  • IIT Kharagpur
  • IIT Roorkee
  • IIT Guwahati
  • IIT BHU Varanasi
  • AIIMS Delhi
  • NIT Tiruchirappalli
  • NIT Rourkela

Join QuestPix, Today!

Get notified first, with exam & curriculum updates, course & test series launch offers, motivation & success stories and free learning resources recommended by toppers.

Chat on WhatsApp