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Differentiability flash cards

Master Differentiability through 85 JEE Advanced-level recall cards, systematically structured one idea at a time. Revise concept-wise, identify the areas where you need improvement, and focus your preparation with greater precision.

Differentiability, question and answer

10 of this chapter's 85 cards, laid out open so you can read straight through. The remaining 75 are in the interactive deck, where the answer stays hidden until you commit to one.

  1. 1.If f(x)f(x) is differentiable at x=ax=a, what can be concluded about continuity, and does the converse hold?

    Differentiability at x=ax=a     \implies continuity at x=ax=a. The converse is false — e.g. f(x)=xf(x)=|x| is continuous at x=0x=0 but not differentiable there.

    Hint: One-way implication only

  2. 2.State the standard test for differentiability of ff at x=ax=a using left-hand and right-hand derivatives.

    ff is differentiable at aa iff Lf(a)=limh0f(a+h)f(a)hLf'(a)=\lim_{h\to0^-}\dfrac{f(a+h)-f(a)}{h} and Rf(a)=limh0+f(a+h)f(a)hRf'(a)=\lim_{h\to0^+}\dfrac{f(a+h)-f(a)}{h} both exist and are equal.

    Hint: LHD = RHD

  3. 3.If ff and gg are both non-differentiable at x=ax=a, is f+gf+g necessarily non-differentiable at x=ax=a?

    No. Sum, difference, or product of two non-differentiable functions can be differentiable; e.g. f(x)=xf(x)=|x|, g(x)=xg(x)=-|x| gives f+g=0f+g=0, which is differentiable everywhere.

    Hint: Counterexample exists

  4. 4.For f(x)=xaϕ(x)f(x)=|x-a|\,\phi(x) where ϕ(x)\phi(x) is continuous, when is ff differentiable at x=ax=a?

    ff is differentiable at x=ax=a if and only if ϕ(a)=0\phi(a)=0 (assuming ϕ\phi is continuous at aa); otherwise the corner from xa|x-a| persists and ff is not differentiable at aa.

    Hint: Kink vanishes only if ϕ(a)=0\phi(a)=0

  5. 5.What does Darboux's theorem say about the derivative function ff', and why is it significant for JEE problems?

    If ff is differentiable on [a,b][a,b], then ff' takes every value between f(a)f'(a) and f(b)f'(b) (Intermediate Value Property), even if ff' itself is not continuous. This is used to rule out certain functions as derivatives of any function.

    Hint: IVP for derivatives, no continuity needed

  6. 6.Examine differentiability of f(x)=x3f(x)=|x|^3 at x=0x=0, and find f(0)f'(0) if it exists.

    For x0x\ge0, f(x)=x3f(x)=x^3; for x<0x<0, f(x)=x3f(x)=-x^3. LHD =limh0h30h=limh0(h2)=0=\lim_{h\to0^-}\dfrac{-h^3-0}{h}=\lim_{h\to0^-}(-h^2)=0. RHD =limh0+h30h=limh0+h2=0=\lim_{h\to0^+}\dfrac{h^3-0}{h}=\lim_{h\to0^+}h^2=0. Since LHD == RHD =0=0, ff is differentiable at 00 with f(0)=0f'(0)=0 — the cubic order overrides the modulus.

    Hint: Expand x3|x|^3 separately for x0, x<0x\ge0,\ x<0 and compute one-sided derivatives.

  7. 7.Show that f(x)=xxf(x)=x|x| is differentiable for all real xx and find f(x)f'(x).

    For x>0x>0, f=x2f=x^2, f=2xf'=2x; for x<0x<0, f=x2f=-x^2, f=2xf'=-2x. At x=0x=0: LHD =limh0h2h=lim(h)=0=\lim_{h\to0^-}\dfrac{-h^2}{h}=\lim(-h)=0; RHD =limh0+h2h=limh=0=\lim_{h\to0^+}\dfrac{h^2}{h}=\lim h=0. So ff is differentiable everywhere with f(x)=2xf'(x)=2|x|.

    Hint: Split into cases x>0,x<0x>0,x<0 and check x=0x=0 via first principles.

  8. 8.Determine all points where f(x)=x+x1f(x)=|x|+|x-1| fails to be differentiable on R\mathbb{R}.

    ff is piecewise linear with slope 2-2 on (,0)(-\infty,0), slope 00 on (0,1)(0,1), and slope 22 on (1,)(1,\infty). At x=0x=0: LHD =20==-2\ne0= RHD. At x=1x=1: LHD =02==0\ne2= RHD. So ff is not differentiable exactly at x=0x=0 and x=1x=1.

    Hint: Write ff as a linear function on each of the three intervals split by 00 and 11.

  9. 9.Is f(x)=sinxf(x)=|\sin x| differentiable at x=πx=\pi? Compare with its behaviour at x=π/2x=\pi/2.

    Near π\pi, sinx\sin x changes sign with sin(π)=cosπ=10\sin'(\pi)=\cos\pi=-1\ne0. For xπx\to\pi^-, sinx>0\sin x>0 so f=sinxf=\sin x, giving LHD =cosπ=1=\cos\pi=-1; for xπ+x\to\pi^+, sinx<0\sin x<0 so f=sinxf=-\sin x, giving RHD =cosπ=1=-\cos\pi=1. LHD \ne RHD, so ff is not differentiable at π\pi. At x=π/2x=\pi/2, sinx=1>0\sin x=1>0 locally, so f=sinxf=\sin x there smoothly, and ff is differentiable with f(π/2)=cos(π/2)=0f'(\pi/2)=\cos(\pi/2)=0.

    Hint: Where does sinx\sin x vanish with nonzero slope, versus stay one-signed?

  10. 10.Check differentiability of f(x)=x23x+2f(x)=|x^2-3x+2| at x=1x=1 and at x=2x=2.

    g(x)=x23x+2=(x1)(x2)g(x)=x^2-3x+2=(x-1)(x-2) has simple zeros at 11 and 22, with g(1)=10g'(1)=-1\ne0 and g(2)=10g'(2)=1\ne0. At a simple zero of a differentiable gg with g0g'\ne0, g|g| always has unequal one-sided derivatives (g(x0))(\mp g'(x_0)), producing a corner. Hence ff is not differentiable at both x=1x=1 and x=2x=2.

    Hint: Use the rule: g(x)|g(x)| is non-differentiable at simple zeros of gg.

Open the interactive deck for the other 75 cards, with self-grading so the ones you keep missing come back.

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