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Hydrocarbon flash cards

Master Hydrocarbon through 88 JEE Advanced-level recall cards, systematically structured one idea at a time. Revise concept-wise, identify the areas where you need improvement, and focus your preparation with greater precision.

Hydrocarbon, question and answer

23 of this chapter's 88 cards, laid out open so you can read straight through. The remaining 65 are in the interactive deck, where the answer stays hidden until you commit to one.

  1. 1.What is the general formula and hybridization of carbon in alkanes?

    General formula CnH2n+2C_nH_{2n+2}; each carbon is sp3sp^3 hybridized with bond angle 109.5109.5^\circ (tetrahedral). All C–C and C–H are single (σ\sigma) bonds.

    Hint: Saturated, single bonds only.

  2. 2.State the Wurtz reaction and its purpose.

    2R-X+2Nadry etherR-R+2NaX2\,R\text{-X} + 2\,Na \xrightarrow{\text{dry ether}} R\text{-}R + 2\,NaX. It couples two alkyl halides to make a symmetrical alkane with double the carbons.

    Hint: Alkyl halide + Na in dry ether.

  3. 3.Why is Wurtz reaction unsuitable for preparing alkanes with an odd number of carbons or unsymmetrical alkanes?

    Two different halides give a mixture of three products (R–R, R'–R', R–R') that are hard to separate. It works cleanly only for symmetrical alkanes.

    Hint: Cross vs self coupling.

  4. 4.Describe Kolbe's electrolytic method for alkanes.

    Electrolysis of aqueous sodium/potassium salt of a carboxylic acid: 2RCOOelectrolysisR-R+2CO2+2e2\,RCOO^- \xrightarrow{\text{electrolysis}} R\text{-}R + 2CO_2 + 2e^- at the anode. Gives symmetrical alkane.

    Hint: Anode decarboxylation of carboxylate.

  5. 5.What is decarboxylation and its reagent for making alkanes?

    Sodium salt of a carboxylic acid heated with soda lime (NaOH+CaONaOH + CaO) loses CO2CO_2: RCOONa+NaOHCaO,ΔR-H+Na2CO3RCOONa + NaOH \xrightarrow{CaO,\Delta} R\text{-}H + Na_2CO_3. Product has one fewer carbon.

    Hint: Soda lime, loses CO2.

  6. 6.How is methane prepared by decarboxylation? Write the reaction.

    CH3COONa+NaOHCaO,ΔCH4+Na2CO3CH_3COONa + NaOH \xrightarrow{CaO,\Delta} CH_4 + Na_2CO_3. Sodium acetate + soda lime gives methane.

    Hint: Sodium acetate.

  7. 7.What does hydrogenation of alkenes/alkynes give, and what is the catalyst?

    Alkene/alkyne +H2Ni/Pt/Pd+ H_2 \xrightarrow{Ni/Pt/Pd} alkane (Sabatier–Senderens reaction with Ni). Unsaturation is removed by syn addition of H2H_2.

    Hint: H2 over Ni/Pt/Pd.

  8. 8.What alkane forms when a Grignard reagent reacts with water?

    RMgX+H2OR-H+Mg(OH)XRMgX + H_2O \rightarrow R\text{-}H + Mg(OH)X. The alkane has the same number of carbons as R. Any source of active H (H2OH_2O, alcohols, NH3NH_3) works.

    Hint: Grignard + active hydrogen.

  9. 9.Compare the two staggered conformations of ethane in terms of stability.

    Ethane has staggered (dihedral 6060^\circ) and eclipsed (00^\circ) forms. Staggered is more stable by about 12.5 kJ/mol12.5\ \text{kJ/mol} due to minimum torsional strain.

    Hint: Torsional strain minimized when H's are apart.

  10. 10.Rank the four conformations of n-butane (about C2–C3) by stability.

    anti (180180^\circ) > gauche (6060^\circ) > eclipsed (partial, 120120^\circ) > fully eclipsed / syn (00^\circ). Anti is most stable (methyls farthest apart).

    Hint: Anti = both methyls opposite.

  11. 11.Why is the gauche conformation of n-butane less stable than anti?

    In gauche the two methyl groups are 6060^\circ apart, causing steric (van der Waals) strain. In anti they are 180180^\circ apart, minimizing steric repulsion.

    Hint: Steric crowding of bulky groups.

  12. 12.Do conformations of ethane/butane represent different compounds? Why can't they be isolated?

    No — they are non-separable spatial arrangements interconvertible by rotation about the C–C σ\sigma bond. The energy barrier is very small, so rotation is fast at room temperature.

    Hint: Rapid interconversion, low barrier.

  13. 13.By what mechanism does chlorination of methane proceed?

    Free-radical substitution (chain mechanism) via three steps: initiation, propagation, termination. Needs UV light or heat.

    Hint: Free radicals, needs hνh\nu.

  14. 14.Write the initiation step of methane chlorination.

    Cl2hν2ClCl_2 \xrightarrow{h\nu} 2\,Cl^\bullet — homolytic cleavage of the Cl–Cl bond by UV light generates chlorine radicals.

    Hint: Homolysis of the halogen.

  15. 15.Write the two propagation steps of methane chlorination.

    Cl+CH4CH3+HClCl^\bullet + CH_4 \rightarrow CH_3^\bullet + HCl then CH3+Cl2CH3Cl+ClCH_3^\bullet + Cl_2 \rightarrow CH_3Cl + Cl^\bullet. The regenerated ClCl^\bullet continues the chain.

    Hint: Radical consumed and regenerated.

  16. 16.Give two possible termination steps in methane halogenation.

    Any radical–radical combination, e.g. Cl+ClCl2Cl^\bullet + Cl^\bullet \rightarrow Cl_2, CH3+CH3C2H6CH_3^\bullet + CH_3^\bullet \rightarrow C_2H_6, or CH3+ClCH3ClCH_3^\bullet + Cl^\bullet \rightarrow CH_3Cl.

    Hint: Two radicals combine, chain ends.

  17. 17.Why does chlorination of methane give a mixture of products?

    Once CH3ClCH_3Cl forms it still has C–H bonds that undergo further substitution, giving CH2Cl2CH_2Cl_2, CHCl3CHCl_3 and CCl4CCl_4. Poly-substitution cannot be avoided.

    Hint: Product still has abstractable H.

  18. 18.What is the order of ease of free-radical halogen substitution of C–H bonds?

    3>2>13^\circ > 2^\circ > 1^\circ (tertiary hydrogen abstracted most easily) because a more substituted radical is more stable.

    Hint: More stable radical forms fastest.

  19. 19.Compare reactivity and selectivity of chlorine vs bromine in radical halogenation.

    Cl2Cl_2 is more reactive but less selective; Br2Br_2 is less reactive but highly selective (strongly prefers 33^\circ H). Fluorination is explosive, iodination is reversible/does not occur.

    Hint: Reactivity vs selectivity trade-off.

  20. 20.What is the combustion reaction of an alkane and its general balanced form?

    CnH2n+2+(3n+12)O2nCO2+(n+1)H2OC_nH_{2n+2} + \left(\dfrac{3n+1}{2}\right)O_2 \rightarrow n\,CO_2 + (n+1)H_2O. Complete combustion is highly exothermic.

    Hint: Complete oxidation to CO2 + H2O.

  21. 21.What happens on incomplete combustion of alkanes (limited O2O_2)?

    Formation of carbon monoxide (COCO) and/or carbon (soot) plus water, e.g. 2CH4+3O22CO+4H2O2CH_4 + 3O_2 \rightarrow 2CO + 4H_2O. Less energy released.

    Hint: Insufficient oxygen → CO/C.

  22. 22.What is controlled oxidation of methane with a catalyst?

    CH4+12O2Cu,523K,100atmCH3OHCH_4 + \tfrac{1}{2}O_2 \xrightarrow{Cu,523K,100atm} CH_3OH (methanol); with Mo2O3Mo_2O_3 it gives HCHOHCHO (methanal). Partial oxidation gives specific oxygenated products.

    Hint: Cu → methanol; Mo2O3 → methanal.

  23. 23.What is isomerisation of alkanes and its catalyst?

    Straight-chain alkane converts to branched-chain isomer on heating with anhydrous AlCl3/HClAlCl_3/HCl, e.g. n-hexane \rightarrow 2-methylpentane. Raises octane number.

    Hint: n-alkane → branched, AlCl3.

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